3 (10 points) Prove that ∫-a^a f(t)dt = 0 if f(x) is odd function on [-a, a].

Name: 3 (10 points) Prove that ∫-a^a f(t)dt = 0 if f(x) is odd function on [-a, a].
Uploaded: 2023-05-24T23:36:26-08:00
Duration: 1 min 23 s
Channel: Numerade
Description: 3 (10 points) Prove that ∫-a^a f(t)dt = 0 if f(x) is odd function on [-a, a].

Question

Subhadeepta Sahoo · Answer

The given integral, considering f is an odd function can be written as minus a to 0 F of x dx pl

Heather Zimmers · Answer

In this problem we know that f of x is an odd function and we&#x27;re trying to show whether or not f

Ankit Gupta · Answer

If f is any function, then we have to prove that a function defined as O of x, which is equal to

Ankit Singh · Answer

So in this problem, basically we need to show that F of 0 is 0 if FX is odd function. So for Fx

Jon Southam · Answer

All right. So we&#x27;re given that F of negative X equals negative F of X, which means that it is od

Question

3 (10 points) Prove that $\int_{-a}^{a} f(t)dt = 0$ if $f(x)$ is odd function on $[-a, a]$.

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