00:01
Okay, so let me call r2 minus a x and let's consider x and y belonging to x.
00:11
We want to show that there is a path joining x and y.
00:16
Well, how can we do this? okay, let me denote by lx like this.
00:24
The set consisting of lines, l of xa, such that this, this line, such that this lines, line l passes from x and a, where a is going to be an element of this guy.
00:40
So such that this one is l, such that l passes from x and a with a belonging to our capital a.
01:02
Now we know that there is just, and if we fix a point, a belonging to this guy, there is a only one line passing from x and a.
01:14
So this pink shows that this guy is countable...