1) Solve for x: -64 + \log_8 (8x - 16) = \log_8 4
Added by Frederick V.
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Step 1
First, let's simplify the expression inside the logarithm: 8x + 16 = 8(x + 2) Now, let's rewrite the expression using the properties of logarithms: log8 (8(x + 2)) = log8 4 Since the base of the logarithm is 8, we can rewrite the equation as an exponential Show more…
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