'(1 + c)y = Ty? 3) Solve: zdz dx'
Added by Anna W.
Step 1
To do that, we can separate the variables by moving all the z terms to one side and all the x terms to the other side: z dz = dx Then, we can integrate both sides: ∫z dz = ∫dx (1/2)z^2 = x + C where C is the constant of integration. Show more…
Show all steps
Close
Your feedback will help us improve your experience
Naresh Bagrecha and 81 other Calculus 3 educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
1. (3y2 +3)dy+(2x−5)dx=0
Israel H.
Solve (4xy^2 + 5y") dx + (2x^2 + 15zy^2 + 3) dy = 0.
Adi S.
(3x - y + 1)dx - (6x - 2y - 3)dy = 0
Gopesh V.
Recommended Textbooks
Calculus: Early Transcendentals
Thomas Calculus
Watch the video solution with this free unlock.
EMAIL
PASSWORD