Use the References to access important values if needed for...

Use the References to access important values if needed for this question. Calculate the number of milliliters of 0.580 M KOH required to precipitate all of the Ag ions in 188 mL of 0.412 M AgNO$_3$ solution as AgOH. The equation for the reaction is: AgNO$_3$(aq) + KOH(aq) $\rightarrow$ AgOH(s) + KNO$_3$(aq) mL KOH

Transcript

00:01 So we're looking at a population of florida panthers, and males have a high frequency of cryptochism.

00:10 Okay, there are two alleles that have complete dominance.

00:14 So the plus allele means the descended, and the negative, the recessive, means the cryptorchid.

00:27 And we look at a sample of 80, and we find eight have these cryptococids.

00:32 Testes.

00:34 They're at hardy wineberg, gliberum, how many are carriers? so any particular panther has two copies of this.

00:41 They can have three possible combinations.

00:44 They can have two plus, one of each, or two minus.

00:49 And since this is a recessive condition, these ones here are going to be the cryptocids.

00:58 And we know that that represents eight out of 80 panthers.

01:03 The other 72 have either one of these.

01:06 Our goal is to work out how many are the carriers.

01:11 So, hardy -weinberg equilibrium has two equations, and i'm going to just use capital a and little a here, because it would get very confusing if i use a plus here.

01:25 So these are the two hardy -weinberg equations.

01:29 First one is allele frequency.

01:31 Every copy of this gene is one of these two alleles.

01:34 As of their frequencies, you'll get 100%.

01:36 Second is genotype frequency.

01:38 Every panther has one of these three genotypes, and at their frequencies you'll also get 100%.

01:45 And this second equation is just what happens if you take the first equation and square both sides...

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