(1)/(2)ln((4p)/(n)) = (1 + (1)/(3) + ... + (1)/(2p - 1)) - ((1)/(2) + (1)/(4) + ... + (1)/(2n))

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\frac{1}{2}ln(\frac{4p}{n}) = (1 + \frac{1}{3} + ... + \frac{1}{2p - 1}) - (\frac{1}{2} + \frac{1}{4} + ... + \frac{1}{2n}) + (\frac{1}{2p + 1} + ... ) \frac{1}{4p - 1} - (\frac{1}{2n + 2} + ... + \frac{1}{4n})